Say it ain’t so…

Milwaukee was just named America’s Drunkest City. What?! Milwaukee beat Chicago for the dubious bragging rights that go with being America’s Drunkest City? Chicago ranks 6th on this list, after Milwaukee, Minneapolis-St. Paul, Columbus, Boston and Austin. Seems a bit strange to me…

6 Comments so far

  1. nikkos (unregistered) on August 24th, 2006 @ 3:05 pm

    At least that explains how they beat us as the best city for singles…

    http://chicago.metblogs.com/archives/2006/07/update_best_us.phtml


  2. Artemis (unregistered) on August 24th, 2006 @ 3:09 pm

    Ah yes, it all makes sense now. :)


  3. nikkos (unregistered) on August 24th, 2006 @ 3:19 pm

    Cool. Now let’s get drunk.


  4. HelOnWheels (unregistered) on August 24th, 2006 @ 3:22 pm

    We’re behind Columbus?? That just doesn’t make sense. Or does it? Personally, if I lived in Columbus I’d want to be drunk all the time so as not to be aware of my surroundings.


  5. Artemis (unregistered) on August 24th, 2006 @ 3:23 pm

    Yes, let’s! We’ll challenge that title! :)


  6. Erik (unregistered) on August 24th, 2006 @ 3:53 pm

    Austin’s going to go down harder than a shooter of JD green label.



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